aseborealtime.blogg.se

How to find the cut off wavelength
How to find the cut off wavelength










Given: Work function of silver = Φ = 2.4 eV= 2.4 x 1.6 x 10 -19ġ0 -34 Js, wavelength of incident light = λ = 6800 Å =

how to find the cut off wavelength

If a light of wavelength 6800 Å is incident on this metal surface, will photoelectron will be ejected? Calculate the incident frequency, the threshold frequency for the metal. The photoelectric work function of a metal is 2.4 eV.

how to find the cut off wavelength

Threshold frequency is 1.2 x 10 15 Hz and no photoelectron will No photoelectrons will be emitted from the metal surface. The frequency of incident light is less than the threshold Given: Work function of silver = Φ = 5 eV = 5 x 1.6 x 10 -19ġ0 -34 Js, wavelength of incident light = λ = 4000 Å =įind: Threshold wavelength of metal = λ o If a light of wavelength 4000 Å is incident on this metal surface, will photoelectron will be ejected? Calculate the threshold frequency for the metal. The photoelectric work function of metal is 5 eV. Calculate the longest wavelength that can cause photoelectric emission from the metal surface. The photoelectric work function of metal is 1.32 eV. Of Planck’s constant is 6.625 x 10 -34 Js Given: Work function of platinum = Φ = 6.3 eV =6.3 x 1.6 x 10 -19 The photoelectric work function of platinum is 6.3 eV and the longest wavelength that can eject photoelectron from platinum is 1972 Å. Threshold frequency of metal is 4.827 x 10 14. J, Planck’s constant = h = 6.63 x 10 -34 Js Given: Work function of silver = Φ = 2 eV = 2 x 1.6 x 10 -19 Calculate the lowest frequency radiation that will cause photoemission from the surface. The photoelectric work function of a metal is 2 eV. Photoelectric work function of the metal is 2.59 eV Given: Threshold wavelength = λ o = 4800 Å = 4800 xġ0 -10 m, speed of light = c = 3 x 10 8 m/s, Planck’s What is the photoelectric work function for metal in eV? Threshold frequency of silver is 8 x 10 14 Hz and itsĪ light of wavelength 4800 Å can just cause photoemission from a metal. = ν o =? Threshold wavelength of silver = λ o = ?

how to find the cut off wavelength

J, speed of light = 3 x 10 8 m/s, Planck’s constant = h = 6.63 x 10 -34 Calculate the threshold frequency and threshold wavelength of silver. The photoelectric work function of silver is 3.315 eV. Given: Frequency of photon = ν = 5.0 x 10 14 Hz, Given: Wavelength of photon = λ = 10 m, speed of light = c =ģ x 10 8 m/s, Planck’s constant = h = 6.63 x 10 -34 JsĮ = hc/λ = (6.63 x 10 -34)(3 x 10 8)/(10)įind the energy of a photon whose frequency is 5.0 x 10 14 Hz ∴ λ = hc / E = (6.63 x 10 -34)(3 x 10 8)/(300įind the energy of a photon in eV if its wavelength is 10 m J, speed of light = c = 3 x 10 8 m/s, Planck’s constant = h =

how to find the cut off wavelength

Given: Energy of photon = E = 300 eV = 300 x 1.6 x 10 -19 Given: Energy of photon = E = 1.0 x 10 -18 J, speed of J, speed of light = c = 3 x 10 8 m/s, Planck’s constant = h = 6.63 x












How to find the cut off wavelength